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The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.

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The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.

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Let AB be the height of the tower and C is the point elevation which is 30 m away from the foot of the tower.

AB (height of the tower)

In right ABC

tan 30° = \(\frac{AB}{BC}\)

\(\frac{1}{\sqrt3}\) = \(\frac{AB}{30}\)

⇒ AB = \(\frac{10}{\sqrt3}\)

Thus, the height of the tower is \(\frac{10}{\sqrt3}\) m.

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