# Forum

As observed from th...

Clear all

# As observed from the top of a 75 m high lighthouse from the sea level, the angles of depression of two ships are 30° and 45°.

1 Posts
2 Users
0 Likes
135 Views
0
Topic starter

As observed from the top of a 75 m high lighthouse from the sea level, the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.

Topic Tags
0

Let AB be the lighthouse of height 75 m. Let C and D be the positions of the ships.

30° and 45° are the angles of depression from the lighthouse.

Draw a figure based on given instructions:

CD = distance between two ships

Step 1: From right triangle ABC,

tan 45° = AB/BC

1= 75/BC

BC = 75 m

Step 2: Form right triangle ABD,

tan 30° = AB/BD

1/√3 = 75/BD

BD = 75√3

Step 3: To find measure of CD, use results obtained in step 1 and step 2.

CD = BD – BC = (75√3 – 75)

= 75(√3-1)

The distance between the two ships is 75(√3-1) m.

Share: