Last seen: Mar 10, 2022
Correct answer: (d) Phosphorus Explanation: Nuisance growth of aquatic plants and bloom-forming algae in natural waters is generally due to high c...
Correct answer: (a) Hepatitis-B Explanation: Sewage from our homes as well as from hospitals are likely to contain many undesirable pathogenic mic...
The given equation is k = (4.5 × 1011 s-1) e-28000 K/T (i) Arrhenius equation is given by, k = Ae-Ea/RT(ii) From equation (i) and (ii), we obt...
First order reaction, k = log It is given that, t1/2 = 3.00 hours k = Therefore, = 0.231 h-1 Then, 0.231 h-1 = log ⇒ log = ⇒ ...
Given, k = 2.0 × 10-2 s-1 T = 100 s [A]o = 1.0 mol-1 Since the unit of k is s-1, the given reaction is a first order reaction. Therefore, k...
Correct answer: (d) Explanation: figure.png (o-xylene) which on ozonolysis give a, b and c.
Correct answer: (a) Explanation: figure.png The ring B has o/p directing and (A) has m-directing group. Hence the product will be figur...
Correct answer: (c) (CH3)2CH – C ≡ CH Explanation: Compound X reacts with ammonical AgNO3 solution, so it must be a terminal alkyne. Formation of ...
Correct answer: (d) Explanation: H3C - C ≡ C - H + CH3CH2 MgCl → H3C - C ≡ C - MgCl + CH3CH3 figure.png
A3B2 ⇌ 3A+2 + 2B-3 3s 2s Ksp = (3s)3(2s)2 Ksp = 108 S5 & s = Ksp = 108 given Ksp = a Comparing a = 108
figure.png Completely filled orbital with mℓ = 0 are = 1+1+1+1+1+1+1 = 7
figure.png ΔH = Ear - Eab = 20 - 65 = -45 KJ/mol |ΔH| = 45 KJ/mol
figure.png One hydrogen bonded H2O molecule
k = log = log = log t75% = 2t50%
The number of halogen forming halic (V) acid HClO3 HBrO3 HIO3
figure.png Reagents used can be (i) Sn + HCl (ii) Fe + HCl (iii) Zn + HCl (iv) H2 – Pd (v) H2 (Raney Ni)
Pbs, CuS, As2S3, CdS are soluble in 50% HNO3 HgS, Sb2S3 are insoluble in 50% HNO3. So, answer is 4.
(H2C2O4.2H2O) = ⇒ x × 10-2 = x = 20
ΔG° = -nFE° = ΔH° - TΔS° = = = = = 25.11 J K-1 mol-1 ∴ Nearest integer answer is 25.
Correct answer: (d) Suspended solids Explanation: Suspended solids impurities is easiest to remove from waste water.