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Raavi Tiwari
@raavi-tiwari
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Joined: May 7, 2021
Last seen: Jun 14, 2021
Topics: 0 / Replies: 2064
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Answer to: The percentage of fresh water on ………….. The process responsible for soil formation is called ……………

2.7 weathering, individual soil minerals, organic matter parent rock rainfall, temperature intercropping ice sheets.

5 years ago
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Answer to: Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B discussed in Section 7.2.

Let us consider, town A at point (0, 0). Therefore, town B will be at point (36, 15). Distance between points (0, 0) and (36, 15) d = = = ...

5 years ago
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Answer to: Find the distance between the following pairs of points: (i) (2, 3), (4, 1) (ii) (-5, 7), (-1, 3) (iii) (a, b), (- a, – b)

Distance formula to find the distance between two points (x1, y1) and (x2, y2) is, say d d = or d = (i) Distance between (2, 3), (4, 1) d = ...

5 years ago
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Answer to: In Figure, D is a point on side BC of ∆ ABC such that BD/CD = AB/AC. Prove that AD is the bisector of ∠BAC.

In the given figure, let us extend BA to P such that; AP = AC. Now join PC. 20q.png Given, BD/CD = AB/AC ⇒ BD/CD = AP/AC By using the c...

5 years ago
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Answer to: In Figure, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. Prove that: (i) ∆ PAC ~ ∆ PDB (ii) PA.PB = PC.PD.

(i) In ∆PAC and ∆PDB, ∠P = ∠P (Common Angles) As we know, exterior angle of a cyclic quadrilateral is ∠PCA and ∠PBD is opposite interior angle, wh...

5 years ago
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Answer to: In Figure, two chords AB and CD intersect each other at the point P. Prove that : (i) ∆APC ~ ∆ DPB (ii) AP.PB = CP.DP

Firstly, let us join CB, in the given figure. (i) In ∆APC and ∆DPB, ∠APC = ∠DPB (Vertically opposite angles) ∠CAP = ∠BDP (Angles in the same seg...

5 years ago
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Answer to: Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides.

Let us consider, ABCD be a parallelogram. Now, draw perpendicular DE on extended side of AB, and draw a perpendicular AF meeting DC at point F. 20q...

5 years ago
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Answer to: In Figure, AD is a median of a triangle ABC and AM ⊥ BC. Prove that : (i) AC^2 = AD^2 + BC.DM + 2 (BC/2)^2

(i) By applying Pythagoras Theorem in ∆AMD, we get, AM2 + MD2 = AD2 ………………. (i) Again, by applying Pythagoras Theorem in ∆AMC, we get, AM2 + MC2...

5 years ago
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Answer to: In Figure, ABC is a triangle in which ∠ABC < 90° and AD ⊥ BC. Prove that AC^2= AB^2+ BC^2 – 2 BC.BD.

By applying Pythagoras Theorem in ∆ADB, we get, AB2 = AD2 + DB2 We can write it as; ⇒ AD2 = AB2 − DB2 ……………….. (i) By applying Pythagoras Theo...

5 years ago
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Answer to: In Figure, ABC is a triangle in which ∠ABC > 90° and AD ⊥ CB produced. Prove that AC^2= AB^2+ BC^2+ 2BC.BD.

By applying Pythagoras Theorem in ∆ADB, we get, AB2 = AD2 + DB2 ……………………… (i) Again, by applying Pythagoras Theorem in ∆ACD, we get, AC2 = AD2 +...

5 years ago
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Answer to: In Figure, D is a point on hypotenuse AC of ∆ABC, such that BD ⊥AC, DM ⊥ BC and DN ⊥ AB. Prove that: (i) DM2 = DN . MC

20q.png (i) Let us join Point D and B. BD ⊥AC, DM ⊥ BC and DN ⊥ AB Now from the figure we have, DN || CB, DM || AB and ∠B = 90 ° Therefore...

5 years ago
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Answer to: In Figure, PS is the bisector of ∠ QPR of ∆ PQR. Prove that QS/PQ = SR/PR

Let us draw a line segment RT parallel to SP which intersects extended line segment QP at point T. Given, PS is the angle bisector of ∠QPR. ∠QPS ...

5 years ago
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Answer to: Tick the correct answer and justify: In ΔABC, AB = 6√3 cm, AC = 12 cm and BC = 6 cm. The angle B is:

20q.png Given, in ΔABC, AB = 6√3 cm, AC = 12 cm and BC = 6 cm. We can observe that, AB2 = 108 AC2 = 144 And, BC2 = 36 AB2 + BC2 = AC2 ...

5 years ago
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Answer to: In an equilateral triangle, prove that three times the square of one side is equal to four times the square of one of its altitudes.

20q.png Let the sides of the equilateral triangle be of length a, and AE be the altitude of ΔABC. ∴ BE = EC = BC/2 = a/2 In ΔABE, by Pythagora...

5 years ago
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Answer to: In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3BC. Prove that 9AD^2 = 7AB^2.

ABC is an equilateral triangle. And D is a point on side BC such that BD = 1/3BC 20q.png Let the side of the equilateral triangle be a, and A...

5 years ago
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