Last seen: Jun 14, 2021
2.7 weathering, individual soil minerals, organic matter parent rock rainfall, temperature intercropping ice sheets.
(a) cultivation
(a) the Sunderban forests
Let us consider, town A at point (0, 0). Therefore, town B will be at point (36, 15). Distance between points (0, 0) and (36, 15) d = = = ...
Distance formula to find the distance between two points (x1, y1) and (x2, y2) is, say d d = or d = (i) Distance between (2, 3), (4, 1) d = ...
20q.png To find AC, we have to use Pythagoras theorem in ∆ABC, is such way; AC2 = AB2+ BC2 AB2 = (1.8 m)2 + (2.4 m)2 AB2 = (3.24 + 5.76) m2 ...
In the given figure, let us extend BA to P such that; AP = AC. Now join PC. 20q.png Given, BD/CD = AB/AC ⇒ BD/CD = AP/AC By using the c...
(i) In ∆PAC and ∆PDB, ∠P = ∠P (Common Angles) As we know, exterior angle of a cyclic quadrilateral is ∠PCA and ∠PBD is opposite interior angle, wh...
Firstly, let us join CB, in the given figure. (i) In ∆APC and ∆DPB, ∠APC = ∠DPB (Vertically opposite angles) ∠CAP = ∠BDP (Angles in the same seg...
Let us consider, ABCD be a parallelogram. Now, draw perpendicular DE on extended side of AB, and draw a perpendicular AF meeting DC at point F. 20q...
(i) By applying Pythagoras Theorem in ∆AMD, we get, AM2 + MD2 = AD2 ………………. (i) Again, by applying Pythagoras Theorem in ∆AMC, we get, AM2 + MC2...
By applying Pythagoras Theorem in ∆ADB, we get, AB2 = AD2 + DB2 We can write it as; ⇒ AD2 = AB2 − DB2 ……………….. (i) By applying Pythagoras Theo...
By applying Pythagoras Theorem in ∆ADB, we get, AB2 = AD2 + DB2 ……………………… (i) Again, by applying Pythagoras Theorem in ∆ACD, we get, AC2 = AD2 +...
20q.png (i) Let us join Point D and B. BD ⊥AC, DM ⊥ BC and DN ⊥ AB Now from the figure we have, DN || CB, DM || AB and ∠B = 90 ° Therefore...
Let us draw a line segment RT parallel to SP which intersects extended line segment QP at point T. Given, PS is the angle bisector of ∠QPR. ∠QPS ...
20q.png Given, in ΔABC, AB = 6√3 cm, AC = 12 cm and BC = 6 cm. We can observe that, AB2 = 108 AC2 = 144 And, BC2 = 36 AB2 + BC2 = AC2 ...
20q.png Let the sides of the equilateral triangle be of length a, and AE be the altitude of ΔABC. ∴ BE = EC = BC/2 = a/2 In ΔABE, by Pythagora...
ABC is an equilateral triangle. And D is a point on side BC such that BD = 1/3BC 20q.png Let the side of the equilateral triangle be a, and A...