Last seen: Oct 19, 2020
(b) 990 mL Explanation: Given N1 = 10N, V1 = 10 ml, N2 = 0.1N, V2 = ? N1V1 = N2V2 or 10 × 10 = 0.1 × V2 or V2 = 10 x 10/0.1, V2= 1000 ml V...
(a) II < I < III < IV Explanation: Mass of 6.023 × 1023 atoms of oxygen = 16 g Mass of one atom of oxygen = 16/6.023 x 1023 = 2.66 x...
(b) 16 g/mol Explanation: The atomic weight of sulphur = 32 In SCl2 valency of sulphur = 2 So equivalent mass of sulphur = 32/2 = 16
(c) 8 g H2 Explanation: Moles of CO2 = 44/44 = 1 No. of molecules NA Moles of O3 = 48/48 = 1 No. of molecules NA Moles of H2 = 8/2 = 4 ...
(a) 1.7 N Explanation: Normality of 10V of H2O2 68 x 10/22.4 = 17 x N ∴ N = 1.78
(c) 50 mL of 0.1 M H2C2O4 Explanation: Meq of A = Meq of B. 0.1 M KMnO4 = 0.5 N KMnO4 ∴ Meq of KMnO4 = 20 × 0.5 = 10 (n factor = 5) Meq of 5...
(b) 40 ml Explanation: Normality of oxalic acid = 6.3 x 1000/63 x 250 = 0.4 N N1V1 = N2V2 = 10 x 0.4 = V x 0.1 = 40 ml
(a) 0.8 Explanation: V.Dmax = XNO2 (V.D)NO2 + XN2O4 (V.D)N2O4 27.6 = X x 23 + (1 - x) x 46 XNO2 = 0.8
(a) CH4 Explanation: Mass ratio of H : C = 1 : 12 However, given mass ratio of H : C = 1 : 3 Therefore, for every C atom, there are 4 H atom...
(b) more than the theoretical weight Explanation: More than theoretical weight since impurity will not contribute.
(d) 0.1 M BaCl2 and 0.075 M FeCl3 Explanation: Effective molarity of BaCl2 = 3 × 0.1 = 0.3 ; effective molarity of FeCl3 = 4 × 0.075 = 0.3
(b) 0.6125 M Explanation: Given WNaOH = 24.5 g No. of moles of NaOH = 24.5/40 moles = 0.6125 moles Molarity of solution = 0.6125 moles/1L = ...
(d) 4480 cm3 Explanation: Ca + 2H2O → Ca(OH)2 + H2 According to the stoichiometry of reaction, 40 gm of Ca on complete reaction with water liber...
(c) 4.48 dm3 Explanation: 2H2O(2 vol.) + Electrolysis → 2H2(2 vol.) + O2(1 vol.) Thus, the volume of hydrogen liberated is twice that of the vol...
(c) 1.4 × 10-21 g Explanation: M.W. = 60 × 12 + 122 = 842 Weight of one molecule = 842/6.02 x 1023 gm = 140 x 10-23gm = 1.4 × 10-21 gm
(c) 33 N Explanation: 70% by weight means Wt. of solute = 70 g Wt. of solution = 100 g ∴ Vcc of solution = mass/density = 100/1.54 We know...
(b) 18.4 M Explanation: 100 gm solution contains 98 gm H2SO4. 100/1.84 c.c contains 98 gm H2SO4. 1000 c.c solution contains = 98/100 x 1.84 ...
(a) Molality Explanation: Temperature does not affect molality as it does not depend upon volume factor.
(c) 2.925 g Explanation: NaCl (xg) + H2SO4(4.9 g) → NaHSO4 (6g)+ HCl(1.825 g) According to law of conservation of mass "mass is neither created ...
(a) 2.88 x 10-3 Explanation: No. of moles = Wt. in g/Mol. wt No. of moles in 200 mg = 200/1000 x 44 = 4.5 x 10-3 moles No. of moles in 1021 ...