Last seen: Oct 19, 2020
(b) If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion. Explanation: Both assertion and reason are c...
(a) If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
(c) If the Assertion is correct but Reason is incorrect. Explanation: A is true. Pressure inside the cell increases due to osmosis. Water enters t...
(a) If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion. Explanation: In polar solvent, acetic acid ...
(a) If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion. Explanation: A molecular mass of benzoic ac...
(d) (i) and (iii) Explanation: Colligative properties depends upon the no. of particles. Since methanol is non electrolyte hence cannot be conside...
(d) C6H12O6 Explanation: ΔTf = Kf x m M = 1000 x Kf x w2 (solute)/ΔTf x w1 (solvent) = (1000 x 1.86 x 1.8)/(0.465 x 40) => M = 180 Mole...
(b) -0.654°C Explanation: As ΔTf = Kf.m ΔTb = Kb.m Hence, we have m = ΔTf /Kf or ΔTf = ΔTb Kf/Kb => [ΔTb = 100.18 - 100 = 0.18°C] As ...
(b) 0.6 Explanation: According to Raoult's law Δp/p° = n/n + N (mole fraction of solute) 10/p° = 0.2 ∴ p° = 50 mm of Hg For other solution o...
(a) 300 g mol-1 Explanation: Molar concentration of urea = 10/60 per dm3 Molar concentration of volatile solute solution = 5/M per 100 ml. or,...
(a) Al2(SO4)3 Explanation: Depression in freezing point ∝ No. of particles. (when concentration of different solutions is equal) Al2(SO4)3 pro...
(d) C6H12O6 Explanation: Glucose is non electrolyte hence depression in freezing point will be minimum, hence freezing point will be highest.
(a) 156 Explanation: Vapour pressure of solution = PA + PB = P°AXA + P°BXB = (120 x 2)/5 + (180 x 3)/5 = 156 mm Hg
(a) equal to second Explanation: Moles of urea = 12/60 = 0.2 Moles of sucrose = 68.4/342 = 0.2 Both are non electrolyte hence lowering of V.P....
(d) 100.156ºC Explanation: ΔTf/ΔTb = i1Kf m/ i2Kbm = 2 x 1.86/3 x 0.52; ΔTf = 0.372. Hence, ΔTb = 0.156ºC i.e., Tb = 100.156ºC
(b) 0.51 Explanation: Weight of solute (w) = 1 g Weight of solvent (W) = 75 g Boiling point of solution = 100.114°C Boiling point of solvent...
(c) 90 Explanation: 2s.png
(b) Shows negative deviation from Raoult’s law Explanation: Shows negative deviation from Raoult’s law. If the attraction between different molecu...
(a) -3°C Explanation: ΔTf ∝ i ∴ ΔTf for KCl/ ΔTf for BaCl2 = i for KCl/i for BaCl2 ∴ ΔTf for KCl/ ΔTf for BaCl2 = 2/3 (∴ ΔTf for KCl = 2) ΔT...
(d) HI Explanation: The value of ΔTb depends upon two factors 'i' and 'm'. It is given that 1 mol of each compound is dissolved in 1 L of solution...