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08/01/2021 3:40 pm
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The kinetic energy of an object of mass, m moving with a velocity of 5 m s-1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity increased three times?
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08/01/2021 3:44 pm
K.E. of an object = \(\frac{1}{2}mv^2\) = 25 J
K.E. of the object with velocity double of initial
= \(\frac{1}{2}\times m(2v)^2\) = \(4 \times (\frac{1}{2}mv^2)\) = 4 x 25 J = 100 J
K.E. of the object with velocity triple of initial
= \(\frac{1}{2}\times m(3v)^2\) = \(9 \times(\frac{1}{2}mv^2)\) = 9 x 25 J = 225 J