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If the radius of the octahedral void is r and radius of the atoms in close packing is R, derive relation between r and R.

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If the radius of the octahedral void is r and radius of the atoms in close packing is R, derive relation between r and R.

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A sphere with centre O, is fitted into the octahedral void as shown in the above figure. It can be observed from the figure that ΔPOQ is right-angled

∠POQ = 90°

Now, applying Pythagoras theorem, we can write,

PQ2 = PO2 + OQ2

⇒ (2R)2 = (R + r)2 + (R + r)2

⇒ (2R)2 = 2(R + r)2

⇒ 2R2 = (R + r)2

⇒ √2R = R + r

⇒ r = √2R - R

⇒ r = (√2 - 1)R

⇒ r = 0.414R

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