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2 cubes each of volume 64 cm^3 are joined end to end. Find the surface area of the resulting cuboid.

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2 cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid.

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The Volume (V) of each cube is = 64 cm3

This implies that a3 = 64 cm3

∴ a = 4 cm

Now, the side of the cube = a = 4 cm

Also, the length and breadth of the resulting cuboid will be 4 cm each. While its height will be 8 cm.

So, the surface area of the cuboid = 2(lb + bh + lh)

= 2(8 × 4 + 4 × 4 + 4 × 8) cm2

= 2(32 + 16 + 32) cm2

= (2 × 80) cm2 = 160 cm2

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