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28/07/2021 10:13 am
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What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm. [Use π = 3.14]
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28/07/2021 10:15 am
Height of conical tent, h = 8m
Radius of base of tent, r = 6m
Slant height of tent, l2 = (r2 + h2)
l2 = (62 + 82)
= (36 + 64) = (100)
l = 10
Again, CSA of conical tent = πrl
= (3.14 × 6 × 10) m2
= 188.4 m2
Let the length of tarpaulin sheet required be L
As 20 cm will be wasted, therefore,
Effective length will be (L - 0.2m).
Breadth of tarpaulin = 3m (given)
Area of sheet = CSA of tent
[(L – 0.2) × 3] = 188.4
L - 0.2 = 62.8
L = 63
Therefore, the length of the required tarpaulin sheet will be 63 m.