Notifications
Clear all
Surface Areas and Volumes
1
Posts
2
Users
0
Likes
528
Views
0
30/07/2021 10:14 am
Topic starter
The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1cm3 of wood has a mass of 0.6g. (Assume π = 22/7)
1 Answer
0
30/07/2021 10:16 am
Inner radius of cylindrical pipe, say r1 = diameter1/ 2
= 24/2 cm = 12cm
Outer radius of cylindrical pipe, say r2 = diameter2/ 2
= 28/2 cm = 14 cm
Height of pipe, h = Length of pipe = 35cm
Now, the Volume of pipe = π(r22-r12)h cm3
Substitute the values.
Volume of pipe = 110×52 cm3
= 5720 cm3
Mass of 1 cm3 wood = 0.6 g
Mass of 5720 cm3 wood = (5720 × 0.6) g
= 3432 g or 3.432 kg.