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26/07/2021 11:53 am
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The inner diameter of a circular well is 3.5m. It is 10 m deep. Find
(i) its inner curved surface area
(ii) the cost of plastering this curved surface at the rate of Rs. 40 per m2.
(Assume π = 22/7)
1 Answer
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26/07/2021 11:54 am
Inner radius of circular well,
r = 3.5/2m = 1.75m
Depth of circular well, say h = 10m
(i) Inner curved surface area = 2πrh
= (2 × (22/7 ) × 1.75 × 10)
= 110
Therefore, the inner curved surface area of the circular well is 110 m2.
(ii) Cost of plastering 1 m2 area = Rs. 40
Cost of plastering 110 m2 area = Rs (110 × 40)
= Rs. 4400
Therefore, the cost of plastering the curved surface of the well is Rs. 4400.