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31/07/2021 11:05 am
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The diameter of a metallic ball is 4.2 cm. What is the mass of the ball, if the density of the metal is 8.9 g per cm3? (Assume π = 22/7)
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31/07/2021 11:06 am
Diameter of a metallic ball = 4.2 cm
Radius(r) of the metallic ball, r = \(\frac{4.2}{2}\) cm = 2.1 cm
Volume formula = \(\frac{4}{3}\) πr3
Volume of the metallic ball = \(\frac{4}{3}\) × \(\frac{22}{7}\) ×2.1 cm3
Volume of the metallic ball = 38.808 cm3
Now, using relationship between, density, mass and volume,
Density = Mass/Volume
Mass = Density × volume
= (8.9 × 38.808) g
= 345.3912 g
Mass of the ball is 345.39 g (approx).