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[Solved] In a hot water heating system, there is cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

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In a hot water heating system, there is cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system. (Assume π = 22/7)

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Height of cylindrical pipe = Length of cylindrical pipe = 28m

Radius of circular end of pipe = diameter/ 2

= 5/2 cm = 2.5cm = 0.025m

Now, CSA of cylindrical pipe = 2πrh,

where r = radius and h = height of the cylinder

= 2 × (22/7) × 0.025 × 28 m2

= 4.4m2

The area of the radiating surface of the system is 4.4m2.

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