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Surface Areas and Volumes
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31/07/2021 10:59 am
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Find the amount of water displaced by a solid spherical ball of diameter
(i) 28 cm (ii) 0.21 m
(Assume π = 22/7)
1 Answer
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31/07/2021 11:03 am
(i) Diameter = 28 cm
Radius, r = \(\frac{28}{2}\) cm = 14cm
Volume of the solid spherical ball = \(\frac{4}{3}\) πr3
Volume of the ball = \(\frac{4}{3}\) × \(\frac{22}{7}\) × 143
= \(\frac{34496}{3}\)
Hence, volume of the ball is \(\frac{34496}{3}\) cm3
(ii) Diameter = 0.21 m
Radius of the ball = \(\frac{0.21}{2}\) m= 0.105 m
Volume of the ball = \(\frac{4}{3}\)πr3
Volume of the ball = \(\frac{4}{3}\) × \(\frac{22}{7}\) × 0.1053 m3
Hence, volume of the ball = 0.004851 m3