A right triangle ABC with sides 5cm, 12cm and 13cm is revolved about the side 12 cm. Find the volume of the solid so obtained.
A right triangle ABC with sides 5cm, 12cm and 13cm is revolved about the side 12 cm. Find the volume of the solid so obtained.
If the triangle ABC Question is revolved about the side 5cm, then find the volume of the solids so obtained. Find also the ratio of the volumes of the two solids obtained in Questions.
A right-angled ΔABC is revolved about its side 5cm, a cone will be formed of radius as 12 cm, height as 5 cm, and slant height as 13 cm.
Volume of cone = \(\frac{1}{3}\) πr2h
where r is the radius and h be the height of cone
= \(\frac{1}{3}\) × π × 12 × 12 × 5
= 240 π
The volume of the cones of formed is 240π cm3.
Required ratio = (result of question 7)/(result of question 8)
= \(\frac{100}{240}\)π = \(\frac{5}{12}\) = 5:12.
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