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A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps.

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A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps. (Assume π =22/7)

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Radius of conical cap, r = 7 cm

Height of conical cap, h = 24cm

Slant height, l2 = (r2 + h2)

= (72 + 242)

= (49 + 576)

= (625)

l = 25 cm

CSA of 1 conical cap = πrl

= (22/7) × 7 × 25

= 550

CSA of 10 caps = (10 × 550) cm2 

= 5500 cm2

Therefore, the area of the sheet required to make 10 such caps is 5500 cm2.

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