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29/07/2021 11:02 am
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A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface of the bowl. (Assume π =22/7)
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29/07/2021 11:08 am
Inner radius of hemispherical bowl = 5cm
Thickness of the bowl = 0.25 cm
Outer radius of hemispherical bowl = (5 + 0.25) cm
= 5.25 cm
Formula for outer CSA of hemispherical bowl = 2πr2, where r is radius of hemisphere
= 2 × (22/7) × (5.25)2 = 173.25
Therefore, the outer curved surface area of the bowl is 173.25 cm2.