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At STP, a container has 1 mole of He, 2 mole Ne, 3 mole O2 and 4 mole N2 without changing total pressure if 2 mole of O2 is removed. The partial pressure of O2 will be decreased by:

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At STP, a container has 1 mole of He, 2 mole Ne, 3 mole O2 and 4 mole N2 without changing total pressure if 2 mole of O2 is removed. The partial pressure of O2 will be decreased by:

(a) 26%

(b) 40%

(c) 58.33%

(d) 66.66%

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Correct answer: (c) 58.33%

Explanation:

PO2 = \(\frac{3}{10}\) x PT

After removing 2 mole of O2,

P'O2 = \(\frac{1}{10}\) x PT

Decrease in partial pressure of O2

= \(\frac{\frac{3P_T}{10} - \frac{P_T}{8}}{\frac{3P_T}{10}}\) x 100

= 58.33%

This post was modified 3 years ago by Shivani siva
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