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09/09/2021 9:25 pm
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A mixture of Ne and Ar kept in a closed vessel at 250 K has a total K.E. = 3kJ. The total mass of Ne and Ar is 30 g. Find mass % of Ne in gaseous mixture at 250 K.
(a) 61.63
(b) 38.37
(c) 50
(d) 28.3
1 Answer
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09/09/2021 9:30 pm
Correct answer: (d) 28.3
Explanation:
K = \(\frac{3}{2}n_TRT\)
⇒ nT = \(\frac{3000 \times 2}{3 \times 250 \times 8.314}\)
3 x 103 = \(\frac{3}{2}n_T\) x 8.314 x 250
\(\frac{x}{20}\) + \(\frac{30-x}{40}\) = \(\frac{2}{8.314}\)
% Ne = 28.3