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Observe the following pattern and supply the missing numbers. 11^2 = 121 101^2 = 10201 10101^2 = 102030201 1010101^2 = ……………………… …………^2 = 10203040504030201

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Observe the following pattern and supply the missing numbers.

112 = 121

1012 = 10201

101012 = 102030201

10101012 = ………………………

…………2 = 10203040504030201

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We observe that the square on the number on R.H.S of the equality has an odd number of digits such that the first and last digits both are 1. And, the square is symmetric about the middle digit. If the middle digit is 4, then the number to be squared is 10101 and its square is 102030201.

So, 10101012 =1020304030201

1010101012 =10203040505030201

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