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09/01/2021 11:19 am
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Two children are at opposite ends of an aluminium rod. One strikes the end of the rod with a stone. Find the ratio of times taken by the sound wave in air and in aluminium to reach the second child.
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09/01/2021 11:29 am
Speed of sound in air, vx = 346 m s-1 Speed of sound in aluminium, v2 = 6420 m s-1
Let the length of the aluminium rod = x m
We know that speed = \(\frac{distance}{time}\)
∴ time = \(\frac{distance}{speed}\)
Time taken in air = \(\frac{x}{346}s\) (∵ distance = x m)
Time taken in aluminium = \(\frac{x}{6420}s\)
Required ratio = \(\frac{x}{346}\) \(\div \)\(\frac{x}{6420}\) = \(\frac{x}{346}\) x \(\frac{6420}{x}\) = 18.55