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09/01/2021 4:50 pm
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If the speed of ultrasound through seawater is 1531 m/s. What is the distance of the seabed from the ship?
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09/01/2021 4:53 pm
Time between transmission and detection t = 342 s.
Speed of ultrasound in seawater = 1531 m/s.
Distance travelled by the ultrasound = 2 x depth of sea = 2d
2d = speed of sound x time
= 1531 x 3.42 = 5236 m
∴ 2d = 5236 m
∴ d = \(\frac{5236}{2}\) = 2618 m
The distance of the seabed from the ship is 2618 m.