The partial pressure of ethane over a solution containing 6.56 × 10-3g of ethane is 1 bar. If the solution contains 5.00 × 10-2g of ethane, then what shall be the partial pressure of the gas?
According to Henry's law, the solubility of gas in a liquid is directly proportional to the pressure of the gas.
X = Kh × P
X is the mole fraction of gas, Kh is the Henry's law constant and P is the partial pressure of the gas.
Also mole fraction of ethane will be directly proportional to its mass.
WP′ = W′P
W is the mass of ethane in first solution and P is the partial pressure of ethane in first solution.
W′ is the mass of ethane in second solution and P′ is the partial pressure of ethane in second solution.
6.56 × 10-3 × P′ = 5.00 × 10-2 × 1P′ = 7.6
Hence, the partial pressure of gas will be 7.6 bar.