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20/10/2021 7:28 pm
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The following data was obtained on performing an experiment for determining the percentage of water absorbed by raisins.
Mass of water in the beaker = 50 g
Mass of dry raisins = 20 g
Mass of raisins after soaking in water = 30 g
Mass of water left in the beaker after the experiment = 40 g
The percentage of water absorbed by raisins will be
(1) 10%
(2) 25%
(3) 45%
(4) 50%
1 Answer
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20/10/2021 7:30 pm
Correct answer: (4) 50%
Explanation:
The percentage of water absorbed is calculated as
\(\frac{Final\;weight - Initial\;weight}{Initial \;weight} \times 100\)
= \(\frac{30-20}{20}\times 100\) = \(\frac{1000}{20}\)
= 50%