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09/07/2021 11:16 am
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Show how would you join three resistors each of resistance 9 ohm so that the equivalent resistance of the combination is 13.5 Ω and 6 Ω.
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09/07/2021 11:21 am
Two resistors in parallel and then one is series
\(\frac{1}{R}\) = \(\frac{1}{R_1}\) + \(\frac{1}{R_2}\)
= \(\frac{1}{9}\) + \(\frac{1}{9}\)
= \(\frac{2}{9}\)
R = \(\frac{2}{9}\) = 4.5 Ω
R' = \(R + R_3\)
= 4.5 + 9 = 13.5 Ω
(ii) Two resistors in series and one in parallel
R = \(R_1 + R_2 \)
= 9 + 9 = 18 Ω
\(\frac{1}{R'}\) = \(\frac{1}{R}\) + \(\frac{1}{R_0}\)
= \(\frac{1}{18}\) + \(\frac{1}{9}\) = \(1 + \frac{2}{18}\)
= \(\frac{3}{18}\)
R' = \(\frac{18}{3}\) = 6 Ω