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The oxidation number of Fe in Na2[Fe(CN)5NO] is

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The oxidation number of Fe in Na2[Fe(CN)5NO] is

(a) +2

(b) +1

(c) +3

(d) -2

1 Answer
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Answer is (a) +2

Explanation:

Given,

\(\overset{+2}{Na_2}[\overset{+2}{Fe}\overset{-5}{(CN)_5}\overset{+1}{NO}]^{-2}\)

Oxidation state of Fe = +2

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