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06/12/2021 12:55 pm
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The oxidation number of Fe in Na2[Fe(CN)5NO] is
(a) +2
(b) +1
(c) +3
(d) -2
1 Answer
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06/12/2021 1:02 pm
Answer is (a) +2
Explanation:
Given,
\(\overset{+2}{Na_2}[\overset{+2}{Fe}\overset{-5}{(CN)_5}\overset{+1}{NO}]^{-2}\)
Oxidation state of Fe = +2
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