Let us assume 3 + 2√5 is rational.

Then we can find co-prime x and y (y ≠ 0) such that 3 + 2√5 = x/y

Rearranging, we get,

\(2 \sqrt{5} = \frac{x}{y}-3\)

\(\sqrt{5} = \frac{1}{2}(\frac{x}{y} - 3)\)

Since, x and y are integers, thus,

\(\frac{1}{2}(\frac{x}{y} - 3)\)

is a rational number.

Therefore, √5 is also a rational number. But this contradicts the fact that √5 is irrational.

So, we conclude that 3 + 2√5 is irrational.