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(i) (2x – 1)(x – 3)...
 
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(i) (2x – 1)(x – 3) = (x + 5)(x – 1) (ii) x^2 + 3x + 1 = (x – 2)^2

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Check whether the following are quadratic equations:

(i) (2x – 1)(x – 3) = (x + 5)(x – 1)

(ii) x2 + 3x + 1 = (x – 2)2

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(i) Given, (2x – 1)(x – 3) = (x + 5)(x – 1)

By using the formula for (a + b)2 = a2+2ab+b2

⇒ 2x– 7x + 3 = x+ 4x – 5

⇒ x– 11x + 8 = 0

Since the above equation is in the form of ax2 + bx + c = 0.

Therefore, the given equation is quadratic equation.

(ii) Given, x2 + 3x + 1 = (x – 2)2

By using the formula for (a + b)2=a2+2ab+b2

⇒ x2 + 3x + 1 = x2 + 4 – 4x

⇒ 7x – 3 = 0

Since the above equation is not in the form of ax2 + bx + c = 0.

Therefore, the given equation is not a quadratic equation.

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