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03/07/2021 10:29 am
Topic starter
Which of the following arguments are correct and which are not correct? Give reasons for your Solution.
(i) If two coins are tossed simultaneously there are three possible outcomes—two heads, two tails or one of each. Therefore, for each of these outcomes, the probability is 1/3
(ii) If a die is thrown, there are two possible outcomes—an odd number or an even number. Therefore, the probability of getting an odd number is 1/2
1 Answer
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03/07/2021 10:30 am
(i) All the possible events are (H,H); (H,T); (T,H) and (T,T)
So, P (getting two heads) = \(\frac{1}{4}\)
and, P (getting one of the each) = \(\frac{2}{4}\) = \(\frac{1}{2}\)
∴ This statement is incorrect.
(ii) Since the two outcomes are equally likely, this statement is correct.