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Probability
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02/07/2021 12:02 pm
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A die is thrown once. Find the probability of getting
(i) a prime number;
(ii) a number lying between 2 and 6;
(iii) an odd number.
1 Answer
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02/07/2021 12:04 pm
Total possible events when a dice is thrown = 6 (1, 2, 3, 4, 5, and 6)
P(E) = (Number of favourable outcomes/ Total number of outcomes)
(i) Total number of prime numbers = 3 (2, 3 and 5)
P (getting a prime number) = 3/6
= 1/2 = 0.5
(ii) Total numbers lying between 2 and 6 = 3 (3, 4 and 5)
P (getting a number between 2 and 6) = 3/6
= 1/2 = 0.5
(iii) Total number of odd numbers = 3 (1, 3 and 5)
P (getting an odd number) = 3/6
= 1/2 = 0.5