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Factorise each of the following: (i) 64a^3 – 27b^3 – 144a^2b + 108ab^2 (ii) 27p^3–(1/216)−(9/2) p^2+(1/4)p

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Factorise each of the following:

(i) 64a3 – 27b3 – 144a2b + 108ab2

(ii) 27p3–(1/216)−(9/2) p2+(1/4)p

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(i) 64a– 27b– 144a2b + 108ab2

The expression, 64a3–27b3–144a2b+108ab2can be written as (4a)3–(3b)3–3(4a)2(3b)+3(4a)(3b)2

64a3 – 27b3 – 144a2b + 108ab2 =
(4a)3–(3b)3 – 3(4a)2(3b) + 3(4a)(3b)2

=(4a–3b)3

=(4a–3b)(4a–3b)(4a–3b)

Here, the identity, (x – y)3 = x3 – y3 – 3xy(x – y) is used.

(ii) 7p3– (1/216)−(9/2) p2+(1/4)p

The expression, 27p3–(1/216)−(9/2) p2+(1/4)p

can be written as (3p)3–(1/6)3–3(3p)2(1/6)+3(3p)(1/6)2

27p3–(1/216)−(9/2) p2+(1/4)p =
(3p)3–(1/6)3–3(3p)2(1/6)+3(3p)(1/6)2

= (3p–16)3

= (3p–16)(3p–16)(3p–16)

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