Forum

Factorise: 27x^3 + ...
 
Notifications
Clear all

Factorise: 27x^3 + y^3 + z^3 – 9xyz

1 Posts
2 Users
0 Likes
225 Views
0
Topic starter

Factorise: 27x3 + y3 + z3 – 9xyz

1 Answer
0

The expression27x3+y3+z3–9xyz can be written as (3x)3+y3+z3–3(3x)(y)(z)

27x3+y3+z3–9xyz  = (3x)3+y3+z3–3(3x)(y)(z)

We know that, x3+y3+z3–3xyz

= (x+y+z)(x2+y2+z2–xy –yz–zx)

27x3+y3+z3–9xyz  = (3x)3+y3+z3–3(3x)(y)(z)

= (3x+y+z)[(3x)2+y2+z2–3xy–yz–3xz]

= (3x+y+z)(9x2+y2+z2–3xy–yz–3xz)

Share:

How Can We Help?