Notifications
Clear all
0
20/09/2020 1:27 pm
Topic starter
You are given that Mass of 37Li = 7.0160 u, Mass of 24He = 4.0026u and Mass of 11He 1.0079u When 20 g of 37Li is converted into 24He by proton capture, the energy liberated, (in kWh), is : [Mass of nucleon = 1 GeV/c2]
(1) 1.33 × 106
(2) 6.82 × 105
(3) 8 × 106
(4) 4.5 × 105
1 Answer
0
20/09/2020 1:29 pm
(1) 1.33 × 106
Explanation:
E = Δmc2
= (1.0079 + 7.0160 – 2(4.0026) × 931
= 1.33 × 106