Forum

Cross-section view ...
 
Notifications
Clear all

Cross-section view of a prism is the equilateral triangle ABC in the figure. The minimum deviation is observed using this prism when the angle of incidence is equal to the prism angle.

1 Posts
2 Users
0 Likes
242 Views
0
Topic starter

Cross-section view of a prism is the equilateral triangle ABC in the figure. The minimum deviation is observed using this prism when the angle of incidence is equal to the prism angle. The time taken by light to travel from P (midpoint of BC) to A is______ × 10-10 s.

(Given, speed of light in vacuum = 3 × 108 m/s and cos30° = \(\frac{\sqrt 3}{2}\))

1 Answer
0

i = A = 60°

δmin = 2i - A

= 2 x 60° - 60° = 60°

μ = \(\frac{sin^{-1}\Big(\frac{\delta_{min} + A}{2}\Big)}{sin^{-1}\Big(\frac{A}{2}\Big)}\)

= \(\sqrt 3\)

Vprism = \(\frac{3 \times 10^8}{\sqrt 3}\)

AP = 10 x 10-2 x \(\frac{\sqrt 3}{2}\)

time = \(\frac{5 \times 10^{-2}}{3 \times 10^8} \times \sqrt3 \times \sqrt3\)

= 5 x 10-10 sec

= 5

Share:

How Can We Help?