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23/12/2021 11:35 am
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What is the change in stopping potential when wavelength changes from 280 nm to 480 nm. φ = 2.65.
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23/12/2021 11:43 am
\(\frac{hc}{\lambda}\) = φ + eV
\(\frac{hc}{\lambda_1}\) - \(\frac{hc}{\lambda_2}\) = e(V1 - V2)
V1 - V2 =\(\frac{hc}{e}\) \(\Big(\frac{hc}{\lambda_1} - \frac{hc}{\lambda_2}\Big)\)
= \(\frac{1240eV\;nm}{e}\) \(\Big(\frac{1}{280nm} - \frac{1}{480nm}\Big)\)
= 1.845V
This post was modified 4 years ago by Reyana09