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Two simple harmonic motion, are represented by the equations y1 = 10 sin (3πt + π/3)

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Two simple harmonic motion, are represented by the equations y1 = 10 sin \(\Big( 3 \pi t + \frac{\pi}{3}\Big)\)

y2 = 5 (sin 3πt + √3 cos 3πt)

Ratio of amplitude of y1 to y2 = x : 1. The value of x is ________.

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y1 = 10 sin 10 sin \(\Big( 3 \pi t + \frac{\pi}{3}\Big)\)

⇒ Amplitude = 10

y2 = 5 (sin 3πt + √3 cos 3πt)

y2 = 10(\(\frac{1}{2}\) sin3πt + \(\frac{\sqrt 3}{2}cos3πt\))

y2 = 10(\(cos \frac{\pi}{3}\) sin3πt + \(sin\frac{\sqrt 3}{2}cos3πt\))

y2 = 10 sin\(\Big( 3 \pi t + \frac{\pi}{3}\Big)\) ⇒ Amplitude = 10

So ratio of amplitudes = \(\frac{10}{10}\) = 1

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