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23/01/2022 2:23 pm
Topic starter
Two plane mirrors M1 and M2 are at right angle to each other show. A point source 'P' is placed at 'a' and '2a' meter away from M1 and M2 respectively. The shortest distance between the images thus formed is (Take √5 = 2.3)
(1) 3a
(2) 4.6 a
(3) 2.3 a
(4) 2√10 a
1 Answer
1
23/01/2022 2:27 pm
Correct answer: (2) 4.6 a
Explanation:
Shortest distance is 2a between I1 & I3
But answer given is for I1 & I2
\(\sqrt{(4a)^2 + (2a)^2}\)
a√20 = 4.47 a