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19/09/2020 11:52 am
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The value of the acceleration due to gravity is g1 at a height h = R/2 (R = radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface the earth. The ratio (d/R) equals:
(1) 4/9
(2) 1/3
(3) 5/9
(4) 7/9
1 Answer
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19/09/2020 11:57 am
(3) 5/9
Explanation:
Given that
gn = gd
GM/(R + h)2 = GM/R3(R - d)
GM/(R + R/2)2 = GM/R3(R - d)
4GM/9R2 = GM/R2(1 - d/R)
4/9 = 1 - d/R
4/9 = 1 - d/R
d/R = 1 - 4/9 = 5/9
d = 5/9R