Notifications
Clear all
0
19/09/2020 6:23 pm
Topic starter
The surface of a metal is illuminated alternately with photons of energies E1 = 4eV and E2 = 2.5 eV respectively. The ratio of maximum speeds of the photoelectrons emitted in the two cases is 2. The work function of the metal in (eV) is……….
1 Answer
0
19/09/2020 6:26 pm
1/2 mv12 = 4 - W ....(1)
1/2 mv22 = 2.5 - W ....(2)
dividing and putting the value v1/v2 = 2
w = 2 eV
This post was modified 4 years ago by nikhil04