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18/09/2020 4:29 pm
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The specific heat of water = 4200 J-kg–1 K–1 and the latent heat of ice = 3.4 × 105 J-kg–1. 100 grams of ice at 0ºC is placed in 200 g of water at 25ºC. The amount of ice that will melt as the temperature of water reaches 0ºc is close to (in grams)
(1) 61.7
(2) 69.3
(3) 64.6
(4) 63.8
1 Answer
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18/09/2020 4:32 pm
(1) 61.7
Explanation:
MSΔT = Mℓ
200/1000 x 4200 x 25 = m x 340 x 103
m = 61.7