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18/09/2020 7:05 pm
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The change in the magnitude of the volume of an ideal gas when a small additional pressure ΔP is applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantity ΔT at constant pressure. The initial temperature and pressure of the gas were 300 K and 2 atm. respectively. If |ΔT| = C|ΔP| then value of C in (K/atm) is ….
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18/09/2020 7:09 pm
PV = nRT
PΔV + VΔP = 0
ΔV = - ΔP/P V ...(i)
In second case
PΔV = -nRΔT
ΔV = nRΔT/P ....(ii)
equating (i) and (ii)
nRΔT/P = - ΔP/P V
C = V/nR
Putting the value of V, n and R, C = 150