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28/12/2021 4:23 pm
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n identical resistance each having value 10 Ω are connected in series with a battery of emf 20 V & internal resistance 10 Ω. The current in a circuit is is. If they are connected in parallel to the same source current is ip. If ip = 20 - is then n will be:
(a) 10
(b) 8
(c) 12
(d) 20
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28/12/2021 4:27 pm
Correct answer: (d) 20
Explanation:
ip = 20 - is
⟹ \(\frac{20}{\frac{10}{n} + 10}\) = 20(\(\frac{20}{10n + 10}\))
⟹ \(\frac{20}{10 + 10n}\) = 20(\(\frac{20}{10n + 10}\))
Therefore, n = 20