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16/09/2020 5:04 pm
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Interference fringes are observed on a screen by illuminating two thin slits 1 mm apart with a light source (λ = 632.8 nm). The distance between the screen and the slits is 100 cm. If a bright fringe is observed on a screen at distance of 1.27 mm from the central bright fringe, then the path difference between the waves, which are reaching this point from the slits is close to :
(1) 2.87
(2) 2 nm
(3) 1.27 μm
(4) 2.05 μm
1 Answer
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16/09/2020 5:08 pm
Correct answer: (3) 1.27 μm
Explanation:
ΔP = dsinθ
= dθ
= dy/D = (10-3 x 1.270 mm)/ 1m = 1.27μm