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29/12/2021 1:45 pm
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Initial number of active in a radioactive element is 1010. If the half-life of a radioactive element is 1 min. What will be the number of active nuclei after 30 sec? [e-0.25 = 0.70].
(a) 0.7 × 108
(b) 0.7 × 1010
(c) 0.7 × 106
(d) 0.7 × 109
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29/12/2021 1:48 pm
Correct answer: (b) 0.7 × 1010
Explanation:
N = \(N_0e^{\frac{\frac{ln2.1}{r_1}}{2}}\)
= 1010 e-0.35 = 0.75 × 1010