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22/12/2021 12:22 pm
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In an L R circuit at steady state energy stored in inductor is 64 J and power consumed by circuit is 640 J. Find time constant for this LR circuit.
(a) 0.2
(b) 0.1
(c) 0.8
(d) 0.25
1 Answer
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22/12/2021 12:31 pm
Correct answer: (a) 0.2
Explanation:
In steady state, energy stored in inductor
\(\frac{1}{2}LI^2\) = 64J .......(1)
Power consumed in steady state,
I2R = 640J .....(2)
Dividing (1) by (2), we get
\(\frac{L}{2R}\) = \(\frac{1}{10}\)
⟹ \(\frac{L}{R}\) = \(\frac{2}{10}\) = 0.2