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If speed V, area A and force F are chosen as fundamental units, then the dimension of Young's modulus will be :

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If speed V, area A and force F are chosen as fundamental units, then the dimension of Young's modulus will be :

(1) FA2V–3

(2) FA2V–1

(3) FA2V–2

(4) FA-1V0

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Correct answer: (4) FA-1V0

Explanation:

Y ∝ FaVbAc

Y = (F/A)

MLT-2/L2 ∝ (M1L1T-2)a(L1T-1)b(L2)c

M1L-1T-2 ∝ MaLa+b+2cT-2a-b

a + b + 2c = –1

–2a + b = –2

a = 1, b = 0, c = –1

Y = F1A-1V0

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