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17/09/2020 5:14 pm
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If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is:
Planck's constant h = 6.63 × 10–34 J.s. Speed of light c = 3 × 108 m/s
(1) 1.1 eV
(2) 1.5 eV
(3) 2.0 eV
(4) 3.1 eV
1 Answer
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17/09/2020 5:16 pm
Correct answer:(4) 3.1 eV
Explanation:
λ = 400 nm
Band gap Eg = hc/λ = 1237.5/400
= 3.09 eV
This post was modified 5 years ago by nikhil04